1.

If the refractive index of a material of an equilateral prism is sqrt3, then angle of minimum deviation will be ..... .

Answer»

`30^@`
`40^@`
`50^@`
`60^@`

SOLUTION :A=60,A+`delta_m=x`,n=`SQRT3`
For rquilateral prism n=`(SIN(A+delta_m)/(2))/(sin(A/2))`
`therefore sqrt3=(sin(x//2))/(sin(60^@/2))`
`implies sin30sqrt3=sin(x//2)`
`implies sin(x//2)=(sqrt3)/(2)`
`thereforex/2=sin^(-1)((sqrt3)/(2))=60^@`
`thereforex=A+delta_m=120impliesdelta_m=120-60=60^@`


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