1.

If the relation between range R and time of flight T is given by R = 5 T^(2) , the angle of throw of the projectile is : (g = 10 m s^(-2) )

Answer»

45°
15°
60°
90°

Solution :Here `(2v^(2)sinthetacostheta)/g=(5xx4v^(2)SIN^(2)THETA)/g^(2)`
or `tantheta=1` if `g=10ms^(-2),` and `theta=45^@`


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