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If the resultant of three forces `vecF_1 = p hati + 3hatj -hatk, vecF_2 = 6hati-hatk and vecF_3 =-5hati +hatj +2hatk` acting on a particle has a magnitude equal to 5 units, then the value of `p` isA. `-6`B. `-4`C. 2D. 4 |
Answer» Correct Answer - B::C Let `vecR` be the resultant. Then `vecR= vecF_1 + vecF_2 + vecF_3 = (p+1) veci + 4hatj` Given, `|vecR| =5`. Therefore, `(p+1)^(2)+ 16 = 25 or `p+1 = pm3` or `p=2, -4` |
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