1.

If the root mean square speed of helium is 4.75 m s^(-1) at 25^(@)C, then its speed will become 9.50 ms^(-1) at

Answer»

`100^(@)C`
`323^(@)C`
`919^(@)C`
`1192^(@)C`

SOLUTION :r.m.s. speed `prop sqrt( T )`
`( 4.75 )/( 9.50) = sqrt(( 298)/( T))`
or `( 4.75^(2))/(9.50) = ( 298)/( T )`
or `T =1192 K`
or `T = 1192 - 273 = 919^(@)C`


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