If the roots of the equation (a - b)x² + (1 - c)X + (c - a) = 0 are e

1.	If the roots of the equation (a - b)x² + (1 - c)X + (c - a) = 0 are equal, prove thatb+c=2a.
Answer» Answer: if ROOTS of equation (a-b)x2+(b-c)X+(c-a)=0, PROVE that b+c=2a . Ask questions ... 1 answers ... C = c-a. For roots to be equal, D=0. (b-c)2 - 4(a-b)(c-a) =0. b2+c2-2bc -4(ac-a2

If the roots of the equation (a - b)x² + (1 - c)X + (c - a) = 0 are equal, prove thatb+c=2a.

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if ROOTS of equation (a-b)x2+(b-c)X+(c-a)=0, PROVE that b+c=2a . Ask questions ... 1 answers ... C = c-a. For roots to be equal, D=0. (b-c)2 - 4(a-b)(c-a) =0. b2+c2-2bc -4(ac-a2

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If the roots of the equation (a - b)x² + (1 - c)X + (c - a) = 0 are equal, prove thatb+c=2a.​

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If the roots of the equation (a - b)x² + (1 - c)X + (c - a) = 0 are equal, prove thatb+c=2a.