1.

If the satellite is stopped suddenly in its orbit and is allowed to fall freely into the earth's surface with what speed it hits the surface of earth?

Answer»

`7.92 km//s`
`11.2" km s"^(-1)`
`8.92" km s"^(-1)`
`5.6" km s"^(-1)`

Solution :Here total energy at height H = Total energyat surface
`0-(GMM)/(R+h)=(1)/(2)mv^(2)-(GMm)/(R )`
`(1)/(2)mv^(2)=(GMm)/(R )-(GMm)/(R+R)=(GMm)/(2R)`
`v=sqrt((GM)/(R ))=sqrt(gR)=sqrt(9.8xx6400xx10^(3))`
`x=7.92 KMS^(-1)`.
CORRECT choice is (a).


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