Saved Bookmarks
| 1. |
if the side of square is 1/2 [x+1] units and diagonal is 3-x/ 2 units then the length of the side square would be |
| Answer» N: If the side of the square is 1/2 × (X + 1) units and the diagonal is (3 - x)/√2 units, then the LENGTH of the side of the square would be?Answer:Step-by-step explanation: Side of the square = 1/2 × (x + 1) units Diagonal of the square = (3 - x)/√2 units The length of side of the square➙ Here we are given the length and diagonal of the square in terms of x. ➙ Now we know that, where a is a side of the square➙ Hence substituting the value for side we get, ➙ Simpifying, ➙ Cancelling √2 on both numerator and denominator, ➙ Now cancelling √2 on both sides of the equation, 3 - x = 1 × (x + 1) 3 - x = x + 1 3 - 1 = x + x 2x = 2 x = 2/2 x = 1 ➙ Hence the value of x is 1 .➙ Now, Side of the square = 1/2 × (x + 1) Substitute value of x Side of the square = 1/2 × (1 + 1) Side of the square = 1/2 × 2 Side of the square = 1 unit ➙ The diagonal of a square = √2 a ➙ The PERIMETER of a square = 4a ➙ The area of a square = a² where a is a side of the square. | |