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If the sides of a triangle are a, b and `sqrt(a^(2) + ab + b^(2))`, then find the greatest angle

Answer» Correct Answer - `120^(@)`
Sides are `a, b, sqrt(a^(2) + ab + b^(2))`
Then the greatest side `c = sqrt(a^(2) + ab + b^(2))`
Let the angle opposite to the greatest side be C.
`rArr cos C = (a^(2) + b^(2) - (a^(2) + ab + b^(2)))/(2ab) = (-1)/(2)`
`rArr C = 120^(@)`


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