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If the sides of a triangle are a, b and `sqrt(a^(2) + ab + b^(2))`, then find the greatest angle |
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Answer» Correct Answer - `120^(@)` Sides are `a, b, sqrt(a^(2) + ab + b^(2))` Then the greatest side `c = sqrt(a^(2) + ab + b^(2))` Let the angle opposite to the greatest side be C. `rArr cos C = (a^(2) + b^(2) - (a^(2) + ab + b^(2)))/(2ab) = (-1)/(2)` `rArr C = 120^(@)` |
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