1.

If the slope of one line of the pair of lines represented by `ax^2 +10xy+ y^2 =0` is four times the slope of the other line, then `a=`

Answer» Let `m` is the slope of one line,then the slope of another line will be `4m`.
So, `(y-mx)(y-4mx) = ax^2+10xy+y^2`
`y^2-4mxy-mxy+4m^2x^2 = ax^2+10xy+y^2`
`=>4m^2x^2-5mxy+y^2 = ax^2+10xy+y^2`
So, `-5m = 10 ` and `a = 4m^2`
`m = -2` and `a= 4**(-2)^2 => a= 16`


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