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If the slope of one line of the pair of lines represented by `ax^2 +10xy+ y^2 =0` is four times the slope of the other line, then `a=` |
Answer» Let `m` is the slope of one line,then the slope of another line will be `4m`. So, `(y-mx)(y-4mx) = ax^2+10xy+y^2` `y^2-4mxy-mxy+4m^2x^2 = ax^2+10xy+y^2` `=>4m^2x^2-5mxy+y^2 = ax^2+10xy+y^2` So, `-5m = 10 ` and `a = 4m^2` `m = -2` and `a= 4**(-2)^2 => a= 16` |
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