If the solenoid in the above question is free to turn about the vertical direction, and a uniform horizontal magnetic field of `0*25T` is applied, what is the magnitude of the torque on the solenoid when its axis makes an angle of `30^@` with the direction of the applied field?A. 0.075NmB. 0.080NmC. 0.081NmD. 0.091Nm

If the solenoid in the above question is free to turn about the vertic

1.	If the solenoid in the above question is free to turn about the vertical direction, and a uniform horizontal magnetic field of `0*25T` is applied, what is the magnitude of the torque on the solenoid when its axis makes an angle of `30^@` with the direction of the applied field?A. 0.075NmB. 0.080NmC. 0.081NmD. 0.091Nm
Answer» Correct Answer - C `Here, M=0.65JT^(-1), B=0.25T, theta=30^(@)` `therefore tau=mB sin theta=0.65xx0.25xxsin 30^(@)` `=0.65xx0.25xx(1)/(2)=0.08125Nm` =0.081 Nm

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