1.

IF the solubility product K_(sp) of a sparingly soluble salt MX_(2) at 25^(@)C is 1.0 xx 10^(-11), the solubility of the salt in mole "litre"^(-1) at this temperature will be

Answer»

`2.46 xx 10^(14)`
`1.36 xx 10^(-4)`
`2.60 xx 10^(-7)`
`1.20 xx 10^(-10)`

SOLUTION :`{:(MX_(2),RARR,M^(+)+,2X_(2)^(-),,K_(SP) = 4S^(3)),(,,(S),(2S)^(2),):}`
`S = 3sqrt((K_(sp))/(4)) = 3sqrt((1 xx 10^(-11))/(4)) = 1.35 xx 10^(-4)`


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