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If the solubility product of CuS is 6 xx 10^(-16) , calculate the maximum molarity of CuS in aqueoussolution. |
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Answer» SOLUTION :MAXIMUM molarity of CuS in aqueous solution = Solubility of CuS in mol `L^(-1)` If S is the solubility of CuS in mol `L^(-1)`, then `CuS IFF Cu^(2+)(s) + S^(2-)(s)` ` therefore S^2=6 xx 10^(-16) " or" S = sqrt(6 xx 10^(-16))` Hence, solubility = `2.45 xx 10^(-8 )"mo "L^(-1)` |
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