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If the solubility product of CuS is 6xx10^(-16), calculate the maximum molarity of CuS in aqueous solution. |
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Answer» Solution :Maximum molarity of CUS in aqueous solution = Solubility of Cus in mol `L^(-1)` If S is the solubility of CuS in mol `L^(-1)`, then `CuShArrunderset("S")(CU)^(2+)+underset(S)(S)^(2-),K_(SP)=[Cu^(2+)][S^(2-)]=SxxS=S^(2)` `therefore""S^(2)=6XX10^(-6)"or"S=sqrt(6xx10^(-16))=2.45xx10^(-8)" mol L"^(-1)` |
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