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If the solubility product of lead iodide is (PbI_2) is 3.2 times 10^-8. Then its solubility in moles/litre will be…….. |
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Answer» `2 times 10^-3 M` `4s^3=3.2 times 10^-8 IMPLIES s=2 times 10^-3 M` |
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