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If the specific heat of lead is 0.03 cal/gm, then the thermal capacity of 500 gm of lead will beA. `5cal//.^(@)C`B. `10cal//.^(@)C`C. `15cal//.^(@)C`D. `20cal//.^(@)C` |
Answer» Correct Answer - C `C=mc=500xx0.03=15cal//.^(@)C` |
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