ANSWER:

If the average SPEED decreases by 120 km/hr & the time increase by 18 MIN and if the speed is INCREASED by 180 km/hr & the time reduces by 18 mins then the average speed of the car is  720 km/hr and the distance travelled is 1080 km.

Step-by-step explanation:

Required formula:

Average Speed =

Let the average speed of the aeroplane be denoted by “x” km/hr and the distance travelled by it be denoted by “y” km/hr.

Step 1:

According to the first condition given in the question and based on the above formula, we can write the eq. as,

⇒ …… (i)

According to the second condition given in the question and based on the above formula, we can write the eq. as,

⇒ …… (ii)

Step 2:

On dividing the eq. (i) by (ii), we get

=  

⇒ =

⇒   =

⇒ 120 (x+180) = 180 (x-120)

⇒ 2x + 360 = 3x - 360  

⇒ x = 720 km/hr

Step 3:

Substituting the value of x = 720 km/hr in eq. (i), we get

y [] =

⇒ y [] =

⇒ y [] =

⇒ y =  * (720*600) *

⇒ y = 1080 km

Thus, the average speed of the car is 720 km/hr and the distance travelled by it is 1080 km.

Plz mark brainliest ❤️❤️

Step-by-step explanation: