1.

If the straight line px - y =0 is outside the circle x^2+ y^2 - 20y +90 =0then?​

Answer»

The INTERSECTION of line and CIRCLE ISX 2 +x 2 m 2 −20mx+90=0⇒x 2 (1+m 2 )−20mx+90=0Since, the line lies outside the circle.∴ D<0⇒400m 2 −4×90(1+m 2 )<0⇒40m 2 <360⇒m 2 <9⇒∣m∣<3


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