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If the sum of all the solutions of the equation `8 cosx.(cos(pi/6+x)cos(pi/6-x)-1/2)=1` in `[0,pi]` is `k pi` then k is equal toA. `20//9`B. `2//3`C. `13//9`D. `8//9` |
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Answer» Correct Answer - C `8 cos x (cos (pi/6+x) cos (pi/6-x)-1/2)=1` `rArr 8 cos x [cos^(2) pi/6- sin^(2) x-1/2]=1` `rArr 8 cos x [1/4-(1-cos^(2) x)]=1` `rArr 8cos^(3)x-6 cos x =1` `rArr 4 cos^(3) x-3 cos x=1/2` `rArr cos 3 x=1/2="cos" pi/3` `3x=2npi pm pi/3, n in Z` Since `x in [0, pi]`, possible values are `3x=pi/3, 2pi pm pi/3` `:. x=pi/9, (5pi)/9, (7pi)/9` sum of solution `=(13 pi)/9` `:. k=13/9` |
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