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If the sum of n terms of a series is`2n^(2)+5n` for all values of n, find its 7th term. |
Answer» Given, `S_(n)=2n^(2)+5n` `implies S_(n-1)=2(n-1)^(2)+5(n-1)=2n^(2)+n-3` `therefore" "T_(n)=S_(n)-S_(n-1)=(2n^(2)+5n)-(2n^(2)+n-3)=4n+3` Hence, `T_(7)=4xx7+3=31` |
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