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If the sum of n terms of an A.P. is `3n^2+5`and its `m^(t h)`term is 164, find the value of m. |
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Answer» Here, we are given, `n/2(2a+((n-1)d) = 3n^2+5n` `(2a-d)+nd = 6n+10` `d = 6 and 2a-d=10` `d=6 and a =8` Now, `m^(th)` term `= a+(m-1)d = 164` `=>8+6(m-1) = 164` `=>6(m-1) = 156` `=> m = 27` |
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