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If the sum of squares of roots of equation `x^(2)-(sin alpha-2)x-(1+sin alpha)=0` is the least, then `alpha` is equal toA. `pi//4`B. `pi//3`C. `pi//2`D. `pi//6` |
Answer» Correct Answer - C `(c )` Let `p`, `q` are roots. `p^(2)+q^(2)=(p+q)^(2)-2pq` `=(sinalpha-2)^(2)+2(1+sin alpha)` `=(sin alpha-1)^(2)=5` For least value `sin alpha=1` `implies alpha=pi//2` |
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