

InterviewSolution
Saved Bookmarks
1. |
If the sum of the coefficient in the expansion of `(alpha^2x^2-2alphax+1)^(51)`vanishes, then find the value of`alpha` |
Answer» We have `(alpha^(2)x^(2)-3alphax+2)^(51)`. `:.` Sum of coefficients `= (alpha^(2)-3alpha+2)^(51)` Since sum of coefficient is zero, `alpha^(2) - 3alpha + 2 =0` `rArr (alpha+2)(alpha-1)=0` `rArr alpha = 1,2` |
|