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If the sum of the first `2n`terms of the A.P. 2, 5, 8, ..., is equal to the sum of the first `n`terms of A.P. 57, 59, 61, ..., then `n`equalsA. 10B. 12C. 11D. 13 |
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Answer» Correct Answer - C We have, `(2n)/(2){2xx2+(2n-1)xx3}=(n)/(2){2xx57+(n-1)xx2}` `rArr" "n(6n+1)=n(n+56)` `rArr" "5n^(2)-55n=0rArrn=11" "[becausen!=0]` |
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