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If the sum of the squaresof the distance of a point from the three coordinate axes is 36, then findits distance from the origin. |
Answer» Let P(x, y, z) be the point. Now, under the given condition, `" "[sqrt(x^(2)+y^(2))]^(2)+[sqrt(y^(2)+z^(2))]^(2)+[sqrt(z^(2)+x^(2))]^(2)=36` or `" "x^(2)+y^(2)+z^(2)=18` Then distance from the origin to point (x, y, z) is `" "sqrt(x^(2)+y^(2)+z^(2))=sqrt(18)=3sqrt(2)` |
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