InterviewSolution
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If the sum of three numbers which are in A.P is 15 and the sum of the squares of the extremes is 58, then those numbers are A) 3, 6, 9 B) 3, 5, 7C) 2, 5, 8 D) 2, 6, 7 |
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Answer» Correct option is (B) 3, 5, 7 Let a - d, a, a+d are required three numbers in A.P. Given that their sum is 15. \(\therefore\) (a - d) + a + (a+d) = 15 \(\Rightarrow3a=15\) \(\Rightarrow a=\frac{15}3=5\) Also given that the sum of the squares of the extremes is 58. \(\therefore(a-d)^2+(a+d)^2=58\) \(\Rightarrow(5-d)^2+(5+d)^2=58\) \((\because a=5)\) \(\Rightarrow 2(5^2+d^2)=58\) \((\because(a-b)^2+(a+b)^2=2(a^2+b^2))\) \(\Rightarrow5^2+d^2=\frac{58}2=29\) \(\Rightarrow d^2=29-5^2=29-25\) \(=4=2^2\) \(\Rightarrow d=2\) \(\therefore a-d=5-2=3\) & \(a+d=5+2=7\) Hence, the required numbers are 3, 5 and 7. Correct option is B) 3, 5, 7 |
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