If the sum of zeroes of polynomial 3x²-kx+1 is equal to its product t

1.	If the sum of zeroes of polynomial 3x²-kx+1 is equal to its product then value of k is
Answer» $\huge \bold \color{green}{ \underline{ \underline \red{required \: answer :- }}}$ polynomial:- 3x²-kx+1 = 0 given:- SUM of ZEROES = product of zeroes solution:- $\bold{let \: \alpha \: \: is \: sum \: of \: zeroes \:} \\ and \: \\ \bold{ \beta \: is \: the \: product \: of \: zeroes}$ according to QUESTION, $\huge \alpha = \beta$ and we know that.. if the equation is in the form of ax²+bx+c = 0 $so \: sum \: of \: zeroes = \huge\frac{ - b}{a}$ and $poduct \: of \: zeroes \: = \huge \frac{c}{a}$ in polynomial 3x²-kx+1 = 0 a = 3 b = -k c = 1 so $\huge\alpha = \frac{ - ( - k)}{3}$ and $\huge \beta = \frac{1}{3}$ $\: since \: \: \: \alpha = \beta \\ \\ \: so \: \: \frac{ - ( - k)}{3} = \frac{1}{3} \\ \\ \: \implies \: k = 1$ $\bold{so \: value \: of \: k \: is \: 1}$