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If the sum to infinity of the series `1+2r+3r^2+4r^3+`is 9/4, then value of `r`is`1//2`b. `1//3`c. `1//4`d. none of theseA. `1//2`B. `1//3`C. `1//4`D. none of these |
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Answer» Correct Answer - B `S=1+2r+3r^(2)+4r^(3)+..` `thereforerS=r+2r^(2)+3r^(3)+4r^(4)+..` `rArr(1-r)S=1+r+r^(2)+r^(3)+..` `=1/(1-r)` `rArrS=1/((1-)^(2))` Given `S=9/4` `rArr1/((1-r)^(2))=9/4` `rArr1-r=pm2/3` `rArrr=1/3or5/3` Hence, r=1/3 as `0ltabsrlt1` |
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