1.

If the temperature of a body is reduced to half of in initial temperature, then radiation power decresed by

Answer»

0.84
0.94
0.06
0.16

Solution :`(P_(2))/(P_(1))=((T_(2))/(T_(1)))^(4)=(((T)/(2))/(T))^(4)`
`(P_(2))/(P_(1))=(1)/(16)`
`(P_(2)-P_(1))/(P_(1))=(1-16)/(16)=-(15)/(16)=93.75%=94%`.


Discussion

No Comment Found

Related InterviewSolutions