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If the temperature of a body is reduced to half of in initial temperature, then radiation power decresed byA. 0.84B. 0.94C. 0.06D. 0.16 |
Answer» Correct Answer - B `(P_(2))/(P_(1))=((T_(2))/(T_(1)))^(4)=(((T)/(2))/(T))^(4)` `(P_(2))/(P_(1))=(1)/(16)` `(P_(2)-P_(1))/(P_(1))=(1-16)/(16)=-(15)/(16)=93.75%=94%`. |
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