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If the temperature of body is increased by 10% the percentage increase in the emitted radiation with be : |
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Answer» `46%` `:.(E_(2)-E_(1))/(E_(1))xx100=(T_(2)^(4)-T_(1)^(4))/(T_(1)^(4))xx100` `((110)^(4)-(100)^(4))/((100)^(4))xx100` `=[(1.1)^(4)-1]xx100` `=(1.46-1)xx100=46%` Correct choice is (a). |
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