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If the third term in the expansion of `(1+x)^mi s-1/8x^2,`then find the value of `mdot` |
Answer» Correct Answer - `m = 1/2` We have, `(1+x)^(m) = 1+mx+(m(m+1))/(2!) x^(2) + "……"` Given that the third therm is `-(1//8)^(2)`, hence `(m(m-1))/(2)x^(2) = =1/8x^(2)` or `4m^(2) - 4m = -1` or `(2m-1)^(2) = 0` or `m =1/2` |
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