1.

If the three plane x = y sin psi+ z sin phi, y = z sin theta + x sin psi, z = x sin phi + y sin theta, intersect in a line, then where theta, phi in (0, (pi)/(2)) theta , phi & psi satisfy

Answer»

`sin ^(2) theta + sin ^(2) PHI + sin ^(2) psi =1`
`sin ^(2) theta + sin ^(2) phi + sin ^(2) psi + 2 sin theta sin theta psi =1`
`COS ^(2) theta + cos ^(2) phi + cos ^(2) psi =1`
`sin ^(2) theta + sin ^(2) phi + sin ^(2) psi =1`

ANSWER :B


Discussion

No Comment Found