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If the tube length of astronomical telescope is 105 cm and magnifying power is 20 for normal setting, then the focal length of the objective is .......... cm. |
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Answer» 10 Tube length `L GE f_0+f_e` …....(1) Magnification m=`(f_0)/(f_e)impliesf_e=(f_0)/(m)`…........(2) From EQN.(1) and (2), `L ge f_0+(f_0)/(m),L=105,m=20,` `105 ge f_0(1+(1)/(20))ge f_0((21)/(20))` `f_0 le (105xx20)/(20) le 100` `implies f_0=100` |
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