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If the `v_(rms)` is `30R^(1//2)` at `27^(@)C` then calculate the molar mass of gas in kilogram.A. 1B. 2C. 4D. `0.001` |
Answer» Correct Answer - D `v_(rms)=sqrt((3RT)/(M))` `sqrt(30^(2)R)=sqrt((3RT)/(M))` `implies 30 xx 30R =(3Rxx300)/(M)` `implies M = (3 xx 300)/(30xx30)=1 gm = 0.001kg`. |
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