1.

If the value of an equilibrium constant for a particular reaction is 1.6xx10^(12), then at equilibrium the system will contain

Answer»

Mostly reactants
Mostly PRODUCTS
SIMILAR amounts of reactants and products
All reactants

Solution :`K=1.6xx10^(12)=[("Product")/("Reactan t")]`
k have high VALUE of products have very high conc than reactant.


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