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If the value of sec B + tan B = r, then the value of sec B - tan B is equal to: |
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Answer» Correct Answer - Option 3 : \(\frac{1}{r}\) Given: sec B + tan B = r Formula Used: sec2θ - tan2θ = 1 a2 - b2 = (a + b) (a - b) Calculation: sec2 B - tan2 B = 1 ⇒ (sec B + tan B) (sec B - tan B) = 1 ⇒ (r) (sec B - tan B) = 1 ⇒ sec B - tan B = 1/r ∴ Value sec B + tan B = r then sec B - tan B is 1/r.
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