1.

If the value of sec B + tan B = r, then the value of sec B - tan B is equal to:

Answer» Correct Answer - Option 3 : \(\frac{1}{r}\)

Given:

sec B + tan B = r

Formula Used:

sec2θ - tan2θ = 1

a2 - b2 = (a + b) (a - b)

Calculation:

secB - tanB = 1 

⇒ (sec B + tan B) (sec B - tan B) = 1

⇒ (r) (sec B - tan B) = 1 

⇒ sec B - tan B = 1/r

∴ Value sec B + tan B = r then sec B - tan B is 1/r.

 



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