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If the vectors a, b and c are coplanar, then `|{:(a, b, c),(a*a, a*b,a*c),(b*a,b*b,b*c):}|` is equal toA. 1B. 0C. `-1`D. None of these 3 |
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Answer» Correct Answer - B Since, a, b and c are coplanar, there must exists three scalars c, y and z are not all zero such that `xa+yb+zc=0" "…(i)` Multiplaying both sides of Eq. (i) by a and b respectivelt, we get `xa*aya*b+za*x=0" "...(ii)` `ab(a+yb*b+zb*x=0" "...(ii)` Eliminating x, y and z from Eqs. (i) ,(ii) and (iii), we get `|{:(a,b,c),(a*a,a*b,a*c),(b*a,b*b,b*c):}|=0` |
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