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If the vectors i - 2xj + 2yk and i + 2xj - 3yk are perpendicular, then the locus of (x , y) is A. a circleB. an ellipseC. a hyperbolaD. none of these |
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Answer» Correct option is B. an ellipse Let \(\vec a=\hat i-2x\hat j+2y\hat k\) and \(\vec b=\hat i+2xj-3y\hat k\) Given that \(\vec a\) and \(\vec b\) are perpendicular. So, \(\vec a-\vec b\) = 0 ⇒ 1 - 4x2 - 6y2 = 0 ⇒ 4x2+ 6y2 =1 Here, vectors are in 3-Dimensions ∴ above equation represents an ellipse .i.e. locus of (x, y) is an ellipse. |
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