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If the velocity (V), acceleration (A) and force (F) are taken as fundamental quantities instead of mass (M), length (L) and time (T), the dimensions of young's modulus (Y) would be : |
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Answer» `FA^(2)V^(-4)` `[ML^(-1)T^(-2)]=[LT^(-1)]^(a)[LT^(-2)]^(b)[MLT^(-2)]^(c)` `ML^(-1)T^(-2)=M^(c )L^(a+b+c)T^(-a-2b-2c)` `:.c=1,a+b+c=-1,-a-2b-2c=-2` On solving, we get `a=-4,b=2` and `c=1`. Hence the correct CHOICE is `(a)`. |
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