)If the vertices of a triangle are (3,1);(4,2); and(5,3). Then area is

1.	)If the vertices of a triangle are (3,1);(4,2); and(5,3). Then area is: *
Answer» Answer: 0 sq. UNITS Step-by-step EXPLANATION: Given: Vertices of the triangle = (3, 1), (4, 2), (5, 3) To find: The area of the triangle Solution: Area of the triangle = $\frac{1}{2}[x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)]$ Here, $x_1=3, x_2=4, x_3=5, y_1=1, y_2=2, y_3=3$ So, the area of the triangle = $\frac{1}{2}[3(2-3)+4(3-1)+5(1-2)]$ ⇒ $\frac{1}{2}[3(2-3)+4(3-1)+5(1-2)]$ ⇒ $\frac{1}{2}[3(-1)+4(2)+5(-1)]$ ⇒ $\frac{1}{2}[-3+8-5]$ ⇒ $\frac{1}{2}[8-8]$ ⇒ $\frac{1}{2}\times 0$ ⇒ $0$ sq. unit ∴ The area of the triangle is $0$ sq. units.