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    				| 1. | 
                                    If the volume of spherical ball is increasing at the rate of `4pi" cc/s"`, then the rate of change of its surface area when the volume is 288 `pi` cc isA. `(4pi)/(3)" cm"^(2)//"sec".`B. `(2pi)/(3)" cm"^(2)//"sec."`C. `4pi" cm"^(2)//"sec."`D. `2pi" cm"^(2)//"sec."` | 
                            
| Answer» Correct Answer - A | |