1.

If the wavelength of light is 5.89 xx 10^(-5) cm, what will be the energy in one photon in the given region of light ? (h= 6.63 xx 10^(-27) " erg".s, c= 3 xx 10^(10)cm//s)

Answer»

Solution :We have, E= hv
and `C= v lamda`
From which we get, `E= (hc)/(lamda)`
`=(6.63 XX 10^(-27) xx 3 xx 10^(10))/(5.89 xx 10^(-5))`
`=3.37 xx 10^(-12)` erg


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