1.

If the Zn^(2+)//Zn electrode is diluted to 100 times then the change in e.m.f.

Answer»

Increase of 59 mV
Decrease of 59 mV
Increase of 29.5 mV
Decrease of 29.5 mV

Solution :`E_(cell)=(0.059)/(n)log((1)/(C))=-(0.059)/(2)log((1)/(100))`
`=-(0.059)/(2)(-2)=0.059V=59mV`. (increase)


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