If There Are 30 Cans Out Of Them One Is Poisoned If A Person Tastes V

1.	If There Are 30 Cans Out Of Them One Is Poisoned If A Person Tastes Very Little He Will Die Within 14 Hours So If There Are Mice To Test And 24 Hours To Test, How Many Mices Are Required To Find The Poisoned Can ?
Answer» Have 6 mice for TESTING, Give each mice contents from 5 cans each 5 5 5 5 5 5 After 14 hours, one of the mice will die So, we will know which 5 cans must have the POISON Then , TAKE the contents of these 5 cans and give to the remaining 5 mice each. We will know in due time which can is poisoned 5C1+5C2+5C3+5C4 = 5 + 10 + 10 + 5 = 30 Have 6 mice for testing, Give each mice contents from 5 cans each 5 5 5 5 5 5 After 14 hours, one of the mice will die So, we will know which 5 cans must have the poison Then , take the contents of these 5 cans and give to the remaining 5 mice each. We will know in due time which can is poisoned 5C1+5C2+5C3+5C4 = 5 + 10 + 10 + 5 = 30

If There Are 30 Cans Out Of Them One Is Poisoned If A Person Tastes Very Little He Will Die Within 14 Hours So If There Are Mice To Test And 24 Hours To Test, How Many Mices Are Required To Find The Poisoned Can ?

Answer»

Have 6 mice for TESTING,

Give each mice contents from 5 cans each

5 5 5 5 5 5

After 14 hours, one of the mice will die

So, we will know which 5 cans must have the POISON

Then , TAKE the contents of these 5 cans and give to the remaining 5 mice each.

We will know in due time which can is poisoned

5C1+5C2+5C3+5C4 = 5 + 10 + 10 + 5 = 30

Have 6 mice for testing,

Give each mice contents from 5 cans each

5 5 5 5 5 5

After 14 hours, one of the mice will die

So, we will know which 5 cans must have the poison

Then , take the contents of these 5 cans and give to the remaining 5 mice each.

We will know in due time which can is poisoned

5C1+5C2+5C3+5C4 = 5 + 10 + 10 + 5 = 30

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