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The Bacteria Has The Probability Of Split Into 3 And Probability To Die Is 1/3rd Of The Total Bacteria.let The Probability Is P. Some Of Them Survived With Probability 1/5.then Which Among The Following Relation Is True ? |
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Answer» PROBABILITY for the BACTERIA to be DYING = 1/3 HENCE probability of survival = 1/5 if they survive, they will be split into 3 more bacteria hence, p = (1/3) + (3* 1/5) Probability for the bacteria to be dying = 1/3 Hence probability of survival = 1/5 if they survive, they will be split into 3 more bacteria hence, p = (1/3) + (3* 1/5) |
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