1.

The Bacteria Has The Probability Of Split Into 3 And Probability To Die Is 1/3rd Of The Total Bacteria.let The Probability Is P. Some Of Them Survived With Probability 1/5.then Which Among The Following Relation Is True ?

Answer»

PROBABILITY for the BACTERIA to be DYING = 1/3

HENCE probability of survival = 1/5

if they survive, they will be split into 3 more bacteria hence, p = (1/3) + (3* 1/5)

Probability for the bacteria to be dying = 1/3

Hence probability of survival = 1/5

if they survive, they will be split into 3 more bacteria hence, p = (1/3) + (3* 1/5)



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