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if `theta=60^(@)`, then `(1)/(2)sqrt(1+sintheta)+(1)/(2)sqrt(1-sintheta)` is equal toA. `cot((theta)/(2))`B. `sec((theta)/(2))`C. `sin((theta)/(2))`D. `cos((theta)/(2))` |
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Answer» Correct Answer - d ` theta=60^(@)` `rArr(1)/(2)sqrt(1+sintheta)+(1)/(2)sqrt(1+60^(@))+(1)/(2)sqrt(1-sin60^(@))` `rArr(1)/(2)sqrt(1+(sqrt(3)/(2)))+(1)/(2)sqrt(1-(sqrt(3)/(2)))` `rArr(1)/(2sqrt(2))(sqrt(2+sqrt(3))+sqrt(2-sqrt(3)))` `rArr(1)/(4)(sqrt((sqrt(3)+1)^(2) ) +sqrt((sqrt(3)-1)^(2)))` `rArr(1)/(4)(sqrt(3)+1+sqrt(3)+1)` `rArr2sqrt(3)/(4)=sqrt(3)/(2)=cos30^(@)=(theta)/(2)` |
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