1.

If theta is eliminated from the equations x=a cos(theta-alpha) and y=b cos(theta-beta), then x^(2)/a^(2) + y^(2)/b^(2) -(2xy)/(ab) cos(alpha-beta) is equal to:

Answer»

`sec^(2)(ALPHA - beta)`
`"cosec"^(2)(alpha - beta)`
`cos^(2)(-beta)`
`SIN^(2)(alpha - beta)`

ANSWER :D


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