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If `theta` is the angle between the lines `ax^2 +2hxy + by^2 =0` , then angle between `x^2 + 2xy sectheta + y^2 =0` isA. `theta `B. `2 theta `C. `(theta)/(2)`D. `3 theta ` |
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Answer» Correct Answer - A Angle between the lines ` ax^(2)+2hxy+by^(2)=0` is ` tan theta=|(2 sqrt(h^(2)-ab))/(a+b)|` For ` x^(2)+2xy sec theta +y^(2)=0` `h= sec theta , a=b=1` `:. tan phi=|(2sqrt(sec^(2) theta-1))/(1+1)|` `=(2 tan theta )/(2)=tan theta ` `:.` Angle between ` x^(2)+2xy sec theta + y^(2)=0` is theta . |
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