1.

If theta is the angle between the transmission axes ofthe polarizer and the analyser and l_0 be the intensity of the polarized light incident on the analyser, then Intensity of transmitted light through analyser would be

Answer»

`(I_0 COSTHETA)^2`
`SQRT2 I_0cos^2theta`
`I_0/sqrt2cos^2theta`
`I_0cos^2theta`

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