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If this solution were placed in a tube of uniform cross-sectional area of 1cm^(2) with a semipermeable membrane at the lower end and this end is dipped in pure water, what will be hight of the vertical column developed? Assume density of the solution as "1 g m L"^(-1). |
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Answer» SOLUTION :`pi=hdg` `"PUTTING"pi="0.2463 atm "=0.2463 xx1.01xx10^(5)Nm^(-2)` `"d = 1 g mL"^(-1)=10^(3)"k m"^(-3), g= "9.81 m s"^(-2),` we get `0.2463xx1.01xx10^(5)=hxx10^(3)xx9.81=2.54m.` |
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